1790 Massachusetts gubernatorial election
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Elections in Massachusetts |
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The 1790 Massachusetts gubernatorial election was held on 5 April 1790 in order to elect the Governor of Massachusetts. Incumbent Governor John Hancock won re-election against former Governor James Bowdoin.[1]
General election
[edit]On election day, 5 April 1790, incumbent Governor John Hancock won re-election by a margin of 12,480 votes against his opponent former Governor James Bowdoin. Hancock was sworn in for his ninth overall term on 30 May 1790.[2]
Results
[edit]Party | Candidate | Votes | % | |
---|---|---|---|---|
Nonpartisan | John Hancock (incumbent) | 14,360 | 86.53% | |
Nonpartisan | James Bowdoin | 1,880 | 11.33% | |
Scattering | 355 | 2.14% | ||
Total votes | 16,595 | 100.00% | ||
Nonpartisan hold |
References
[edit]- ^ "John Hancock". National Governors Association. Retrieved 24 May 2024.
- ^ "MA Governor". ourcampaigns.com. 29 March 2019. Retrieved 24 May 2024.
Categories:
- 1790 Massachusetts elections
- 1790 in Massachusetts
- Massachusetts gubernatorial elections
- 1790 United States gubernatorial elections
- 1790s in Massachusetts
- 1790s Massachusetts elections
- 1790 elections
- 1790 elections in North America
- 1790 elections in the United States
- United States gubernatorial elections in the 1790s
- Non-partisan elections
- Government of Massachusetts